1+2/x+5/x^2=0

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Solution for 1+2/x+5/x^2=0 equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

2/x+5/(x^2)+1 = 0

2*x^-1+5*x^-2+1 = 0

t_1 = x^-1

5*t_1^2+2*t_1^1+1 = 0

5*t_1^2+2*t_1+1 = 0

DELTA = 2^2-(1*4*5)

DELTA = -16

DELTA < 0

x belongs to the empty set

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